1848 United States presidential election in Iowa

Main article: 1848 United States presidential election

1848 United States presidential election in Iowa

November 7, 1848

Nominee Lewis Cass Zachary Taylor Party Democratic Whig Home state Michigan Louisiana Running mate William O. Butler Millard Fillmore Electoral vote 4 0 Popular vote 11,238 9,930 Percentage 50.46% 44.59%

County Results Cass   40-50%   50-60%   60-70% Taylor   40-50%   50-60%

President before election James K. Polk Democratic Elected President Zachary Taylor Whig

The 1848 United States presidential election in Iowa took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Iowa voted for the Democratic candidate Lewis Cass in the state's first presidential election, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Iowa by a margin of 5.87%.

This is one of just three times (the others being 1988 and 2000) that a losing Democrat carried Iowa. Taylor became the first of currently only six American presidents to have never won Iowa since its statehood.

The 1848 election in Iowa began a trend in which the state would vote the same as neighboring Wisconsin, as the two states have voted in lockstep with each other on all but 6 occasions - 1892, 1924, 1940, 1976, 2004, and 2020.

Results

1848 United States presidential election in Iowa
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Lewis Cass of Michigan	William O. Butler of Kentucky	11,238	50.46%	4	100.00%
	Whig	Zachary Taylor of Louisiana	Millard Fillmore of New York	9,930	44.59%	0	0.00%
	Free Soil	Martin Van Buren of New York	Charles F. Adams, Sr. of Massachusetts	1,103	4.95%	0	0.00%
Total				22,271	100.00%	4	100.00%

See also

• United States presidential elections in Iowa